wandelaar

More tests for the non-random character of the I Ching

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In this topic I wish to discuss some other possibilities for testing the non-random character of the I Ching. We already had a discussion about one method. See here: https://www.thedaobums.com/topic/46950-tests-for-the-non-random-character-of-the-i-ching/  If you want to talk about that method than please post your messages there.

 

The same as applies in the other topic applies here: The purpose of this topic is exploring ways to test whether or not working with the I Ching shows patterns in the found hexagrams that are impossible to explain when the hexagrams that turn up are purely random. This topic is expressly not about belief or disbelief or anecdotal evidence! So please don't spam this topic to death as happened with previous topics of mine. If you are not interested in exploring systematic ways to test the I Ching than please leave us alone.

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How about this:

 

The number π is completely determined in its binary expansion. For more about pi see: https://en.wikipedia.org/wiki/Pi

and about its binary expansion see: https://oeis.org/A004601 Now the zero's and one's from this expansion are pseudorandom, they are completely determined by the number π but their appearance in the expansion looks random nevertheless. And there is no way that a situation on the current moment or a question asked could be of influence on the placement of the zero's and one's in π's binary expansion. So when using the string of zero's and one's from the binary expansions of π in stead of the results of throwing coins would give equally satisfying results in consulting the I Ching, than we can conclude that the I Ching doesn't need paranormal influences on random processes for its use as an oracle. 

Edited by wandelaar

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For those willing to try this at home, here's a piece of π's binary expansion:

http://www.befria.nu/elias/pi/binpi.html

 

I will be happy to hear the results! Does using the zero's and one's from the expansion work just as well as throwing coins? (Let's use: 0 = Heads, 1 = Tails)  I suggest that you start with the first three digits to represent the result of the first throwing of the three coins. The second three digits represent the result of the second throwing of the three coins. And so on...

Edited by wandelaar

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