Help with Maths ?

[Stigweard]

Excuse asking this here but I can't get my head around this:

 

x = y-(0.38196601*(y-(0.61803399*y)))

 

If we know the value for x (say x = 3) what is the formula to calculate y ????

 

 

 

Thanks in advance.

[orb]

Excuse asking this here but I can't get my head around this:

 

x = y-(0.38196601*(y-(0.61803399*y)))

 

If we know the value for x (say x = 3) what is the formula to calculate y ????

 

Thanks in advance.

 

 

Ok stig here's what I have: from what I understand the issue here is that they are trying to confuse you with the notation making it all look crazy therefore we will substitute the scary numbers for the beginning with letter.

 

so:

 

I unnderstand that your * = multiplication

and you have x = 3

 

then we substitute:

 

0.38196601 = a

0.6180399 = b

 

so we will have

 

x = y - a(y-by)

which becomes

 

x = y - ay + aby

x = y(-a+ab)

 

now all you have to do is calculate what's in the parethesis

 

which in you case

 

0.38196601 = a

0.6180399 = b

 

so you get x = y(-0.38196601+0.6180399*0.38196601)

 

and you get smth like x = y(-0.145895775376201)

then you replace x with 3 like you said

 

so 3 = y(-0.145895775376201)

so

y = 3 / -0.145895775376201

 

y = 20.562624190209210767200795911796

 

 

Since I'm in a rush I didn't verify any calculation but that should be the way to solve it.

 

I hope it helps

[mwight]

I think this got it LOL sorry.

http://www.intmath.com/Basic-algebra/Algeb...blem-solver.php

 

3=y-(0.382)(y-0.618y)

 

 

Since y is on the right-hand side of the equation, switch the sides so it is on the left-hand side of the equation.

 

y-(0.382)(y-0.618y)=3

 

 

Since y and -0.618y are like terms, add -0.618y to y to get 0.382y.

 

y-(0.382)(0.382y)=3

 

 

Multiply 0.382 by 0.382y to get 0.146y.

 

y-(0.146y)=3

 

 

Multiply -1 by the 0.146y inside the parenthesis.

 

y-0.146y=3

 

 

Since y and -0.146y are like terms, add -0.146y to y to get 0.854y.

 

0.854y=3

 

 

Divide each term in the equation by 0.854.

 

 

 

 

Cancel the common factor of 0.854.

 

 

 

 

Divide 3 by 0.854 to get 3.512.

 

y=3.512

Edited August 28, 2008 by mwight

[Smile]

0.38196601 = a

0.61803399 = b Missed 3

 

so we will have

 

x = y - a(y-by)

which becomes

 

x = y - ay + aby

x = y(-a+ab) Wrong. It's x = y*(1-a+ab)

 

x = y*(1-a+ab)

0.38196601 = a

0.61803399 = b

x=y*(1 - 0.38196601 + 0.38196601 * 0.61803399)

x=y*(0.61803399 + 0.38196601 * 0.61803399)

x=3

y=3 / (0.61803399 * 1.38196601)

y=3 / 0.854101967

y=3.51246118

Something like that

Edited August 28, 2008 by Smile

[Stigweard]

LOL Not yet fellas

 

I am creating a logarithmic sequence of which I knew the upper limit, i.e y = 39.900

 

Using the formula x = y-(0.38196601*(y-(0.61803399*y)))

 

We get x = 34.079

 

At each subsequent step downt the scale the previous x becomes the new y (i.e. 34.079 becomes y and so on) this scale goes down as such:

 

39.900 34.079 29.107 24.860 21.233 18.135 15.489 13.229 11.299 9.651 8.243 7.040 6.013 5.136 4.386 3.746 3.200

 

Now what I want to be able to do is to allocate a lower parameter value (3.200 for example) and calculate the scale from the bottom up.

 

Cheers

 

 

 

 

x = y*(1-a+a*

0.38196601 = a

0.61803399 = b

x=y*(1 - 0.38196601 + 0.38196601 * 0.61803399)

x=y*(0.61803399 + 0.38196601 * 0.61803399)

x=3

y=3 / (0.61803399 * 1.38196601)

y=3 / 0.854101967

y=3.51246118

Something like that

 

 

YAYAYAYAYAYYAYAYA!!!!!!! That's it.

 

******* BIG HUGS FOR SMILE **********

 

 

Thanks champ I owe you one.

[STALKER2002]

LOL Not yet fellas

 

I am creating a logarithmic sequence of which I knew the upper limit, i.e y = 39.900

 

Using the formula x = y-(0.38196601*(y-(0.61803399*y)))

 

We get x = 34.079

 

At each subsequent step downt the scale the previous x becomes the new y (i.e. 34.079 becomes y and so on) this scale goes down as such:

 

39.900 34.079 29.107 24.860 21.233 18.135 15.489 13.229 11.299 9.651 8.243 7.040 6.013 5.136 4.386 3.746 3.200

 

Now what I want to be able to do is to allocate a lower parameter value (3.200 for example) and calculate the scale from the bottom up.

 

Cheers

YAYAYAYAYAYYAYAYA!!!!!!! That's it.

 

******* BIG HUGS FOR SMILE **********

 

 

Thanks champ I owe you one.

Hi! May my math of Yin-Yang Symbol will also be interesting for you:

My Webpage

[Smile]

Stigweard, you're welcome.

Stalker, welcome to Taobums. About time you migrated here from HT forum. Take it easy on Russian news though.

[turbo]

here:

x = y-(0.38196601*(y-(0.61803399*y)))

x= y-(.381*(y-.618y)) -->subtract (1-.618)

x= y-(.381*(.381y)) --> multiply .38196601 * .38196601 = .145898032

x= y-.145y --> subtract 1-.145 = .85410196

x= .845y

y=x/.85410196

 

substitute values for x to solve for y.

[Mal]

x = y*(1-a+ab)

0.38196601 = a

0.61803399 = b

x=y*(1 - 0.38196601 + 0.38196601 * 0.61803399)

x=y*(0.61803399 + 0.38196601 * 0.61803399)

x=3

y=3 / (0.61803399 * 1.38196601)

y=3 / 0.854101967

y=3.51246118

 

WTF?

o.k. it's not THAT bad, but we wonder why we can't understand Drew